Chugging
Question
Solution
Idea
This question is another math question, which is about arithmetic progression. It's rather easy, nothing much to talk about.
Code
https://github.com/mendax1234/Coding-Problems/blob/main/kattis/chugging/chugging.c
#include <stdio.h>
int calc_sum(int a1, int d1, int n)
{
int sum = a1;
for (int i = 1; i < n; i += 1)
{
sum += a1 + d1 * i;
}
return sum;
}
int main()
{
int n;
scanf("%d", &n);
int a1, d1, a2, d2;
scanf("%d %d\n%d %d", &a1, &d1, &a2, &d2);
int sum1 = calc_sum(a1, d1, n);
int sum2 = calc_sum(a2, d2, n);
if (sum1 > sum2)
{
printf("Bob\n");
}
else if (sum1 < sum2)
{
printf("Alice\n");
}
else
{
printf("=\n");
}
}
Last updated